“Isobaric Process” MHT-CET Class 12 Physics Crash Course | Chapter Thermodynamics
In this session G.S. Khairnar discussed the theory and MCQ’s of “Isobaric Process”. The session will be useful for all the aspirants of MHT-CET 2022. The session will be in Marathi and English.
Isobaric Process:-
Hello dear students, in previous article we have learnt about the isothermal process, in which the temperature of system remains constant, and no internal energy is gained by the system. i.e. △T=0. It is constant temperature process. The transfer of heat to surrounding takes place at very slow rate, due to which the thermal equilibrium is maintained throughout the process. In this article we are going to discuss the system in which the pressure is remains constant.
Let’s learn the concept of isothermal process….!
The process in which the pressure of system remains constant throughout is known as isobaric process. i.e. △P=0. Since temperature in this process is changes, hence none of the quantity i.e. heat, internal energy and work is zero.
According to Boyle’s law, at constant temperature, pressure of given mass of gas is inversely proportional to its volume.
Then PV= constant
Or, P1V1=P2V2
Consider the expansion of gas under isobaric system, in which the volume of gas changes from Vi to Vf with the corresponding temperature Ti to Tf.
The Work done during the process is given as,
We know that the change in internal energy per unit change in temperature is known as the specific heat capacity at constant volume i.e. Cv.
From this equation we can conclude that, in isobaric process temperature of system changes, which changes the internal energy of system and does the work also.
The graphical representation of isothermal system is known as ‘isobar’, which is the graph between pressure (P) vs volume (V).
